topic ok, but can a subdivision in Intel® Embree Ray Tracing Kernels

Displacement map

Al_N_ — Wed, 12 Aug 2015 04:55:57 GMT

Hi, can I use triangle geometry as oppose to quads for displacement mapping? If so, is there an example anywhere? Thank you.

No, the displacement mapping

SvenW_Intel — Wed, 12 Aug 2015 13:50:48 GMT

No, the displacement mapping is only implemented for subdivision surfaces.

ok, but can a subdivision

Al_N_ — Wed, 12 Aug 2015 15:53:36 GMT

ok, but can a subdivision surface be triangles instead of quads? In the displacement example, it uses quads and RTC_FACE_BUFFER is set with an array of only 4s and the documentation say that it can be 3 or 4 so I assume 3 is for triangles?

Yes you can render each

SvenW_Intel — Thu, 13 Aug 2015 14:21:18 GMT

Yes you can render each triangle mesh also as subdivision surface. However, triangle meshes sometimes have large triangle fans that the Embree subdivision implementation can currently not handle. It will drop these fans during rendering.

I see. I did a test, like a

Al_N_ — Thu, 13 Aug 2015 16:15:46 GMT

I see. I did a test, like a cube and a sphere made of triangles but at render time, each triangles are smaller and they look more round, each triangles have 6 edges instead of 3 and there is space in between each one, none ate touching anymore. Any ideas?

What values did you set for

BenthinC_Intel — Sat, 15 Aug 2015 19:26:45 GMT

What values did you set for the edge tessellation levels and did you specify a displacement function for the simple cube and sphere geometry?

Embree's interpolation tutorial uses also some simple triangle-based geometry, so you could double-check the tutorial code with your implementation.

If there are still artifacts visible could you post some example code so that we can quickly reproduce the issue?

Thanks a lot,

Carsten.

Thanks for your answer. All I

Al_N_ — Sat, 15 Aug 2015 19:34:42 GMT

Thanks for your answer. All I did was use your displacement tutorial and changed the values in the arrays to reflect triangles as oppose to quad (indices too and changed face from 4 to 3). I exit the displacement function just to see if the cube will show as a cube, and also set the tessellation value from 256 to 0 and still each triangles are showing with 6 sides and smaller so there is a good visible gap between each triangles. If possible, could you modify the tutorial so it include a simple triangle mesh as oppose to a quad mesh and perhaps include it in the list of tutorials?

In line 65 of the

SvenW_Intel — Mon, 17 Aug 2015 06:22:51 GMT

In line 65 of the displacement tutorial you can switch the cube to a triangle cube.

You are right that there are some cracks at the triangles, probably caused by wrong geometry normals. We will work on that.

ok thanks

Al_N_ — Mon, 17 Aug 2015 20:24:48 GMT

ok thanks

Does it matter if there are

Al_N_ — Tue, 18 Aug 2015 00:36:59 GMT

Does it matter if there are duplicate vertices? like 3 per triangle and for a cube, 36 vertices and 36 indices?

You can have duplicate

SvenW_Intel — Tue, 18 Aug 2015 05:56:19 GMT

You can have duplicate vertices, this will not be a problem.

ok because I'm getting weird

Al_N_ — Wed, 19 Aug 2015 00:53:41 GMT

ok because I'm getting weird results. Here is the cube (triangulated) rendered using rtcNewTriangleMesh and how it turns out using rtcNewSubdivisionMesh without a displacement function and levels set to 0 or 256 same result... https://www.imageupload.co.uk/images/2015/08/19/untitled1.png https://www.imageupload.co.uk/images/2015/08/19/untitled2.png

Ok, your cube is rendered

SvenW_Intel — Wed, 19 Aug 2015 05:29:20 GMT

Ok, your cube is rendered that way because you no not have shared vertices. If the vertices are not shared you still define a valid subdivision surface, however, each triangle will get subdivided separately of the other triangles, resulting in the subdivision you see. To properly render the cube you have to share all vertices.

ah, ok, thank you very much.

Al_N_ — Thu, 20 Aug 2015 19:34:00 GMT

ah, ok, thank you very much. One more question, the PrimID Embree return is based on what exactly?

"primID" refers to the n-th

BenthinC_Intel — Sun, 23 Aug 2015 09:30:25 GMT

"primID" refers to the n-th primitive in an object. "geomID" to the n-th object.

Thank you.

Al_N_ — Sun, 23 Aug 2015 16:18:04 GMT

Thank you.