Access violation reading location 0xFFFFFFFFFFFFFFFF.

Brooks_Van_Horn — Tue, 08 Mar 2016 16:36:37 GMT

The debug statement says nothing is wrong. This is Debug x64 mode in MSVS 2013. Here is the code

Module Horn

! Table of random numbers from fitted Pearson Distribution
! pseudo random number seed whoich can be changed by user

Integer(4),parameter::   Rand = 20000
Integer(4),Save,Public:: sType
Real(8),Save,Public::    sAvg, sCm2, sCm3, sCm4, sKapa, sBeta1, sBeta2, &
                           sMin, sMax, sKSVal, sKSStat80, sKSStat90, sKSStat95, &
                             sKSStat99
Real(8),Save,Public::    Draw(0:Rand+1)
Real(8),Save,Public::    rArray(0:Rand+1)

End Module Horn

Subroutine GetRS (myNumRS)
Use Van
Use Horn
Use Howe
Use PearsonGlobals
Use Random
USE, INTRINSIC :: IEEE_EXCEPTIONS

Implicit None

Integer(4), intent(inout) :: myNumRS <======== this has a value of 5000

Real(8),Save:: w, h, rdm, xx
Real(8),Save:: Diff, box
Integer(4),Save:: L, jk, lp, mm, Limit, iStrt, ErrNo, Last, i
Logical(4),Save:: logic

!   This routine will generate 'myNumRS' pseudo-random variates from
!   one of the Pearson Curve types (pType) which were used to create
!   the CDF and xVals arrays which are used to calculate the pseudo-
!   random variables.

     If ((pType <= 0) .or. (pType >= 9)) Then                    <============= pType = 8
        gMyErrors = 5
        myNumRS = 0
        return
     End If
     raw1 = 0.d0
     raw2 = 0.d0
     raw3 = 0.d0
     raw4 = 0.d0
     iStrt = gTotalRS + 1
     Limit = min(Rand, myNumRS)
     box = 1.d0 / Dble(Limit)
     Diff = Upper - Lower                             <=============== Diff is about 12
     h = Diff / Dble(Nr)
     xx = Dble(MaxIndex)                            <=============== MaxIndex = 1000 and is whare CDF(*) has values
!    draw 'Limit' pseudo-random variables from the Pearson Type Curve
     Do jk = iStrt, Limit
       logic = (1 == 1)
       L = 0
       rdm = RanF(1)                                 <============= 0.0 < rdm < 1.0
       if ((rdm <= 1.d-75) .or. (rdm >= 1.d0)) Then
          gMyErrors = -jk
          return
       End If
       mm = max(1,min(NINT(xx), NINT(xx * rdm)))
       Do lp = Index(mm-1), index(mm+1)
         If ((Cdf(lp) > rdm) .and. logic) Then
           logic = (1 == 3)
           L = lp
           Exit
         End if
       End Do

       ! rdm lies between Cdf(L) and Cdf(L-1)
       w = ((rdm - Cdf(L-1))/(Cdf(L) - Cdf(L-1)))
       If ((w < 0.d0) .or. (w > 1.d0)) Then
          gMyErrors = L
          Return
       End If
       Draw(jk) = w * h + xVal(L-1)
       w = (Draw(jk) - Lower) / Diff
       If ((w < 0.d0) .or. (w > 1.d0)) Then
          gMyErrors = L
          Return
       End If
     End Do
     sMin = 1.d+75
     sMax = - sMin
     do jk = 1, Limit
       rdm = Draw(jk)
       sMin = min(sMin, rdm)
       sMax = max(sMax, rdm)
       raw1 = raw1 + rdm
       raw2 = raw2 + rdm**2
       raw3 = raw3 + rdm**3
       raw4 = raw4 + rdm**4
     end do
     w = Dble(Limit)
     raw1 = raw1 / w
     raw2 = raw2 / w
     raw3 = raw3 / w
     raw4 = raw4 / w
     Call Moments(sAvg, sCm2, sCm3, sCm4, raw1, raw2, raw3, raw4) <======== converts moments about zero to central moments
     Call GetPT(sAvg, sCm2, sCM3, sCm4, sType, sKapa, ErrNo)
     sBeta1 = scm3*scm3/scm2**3
     sBeta2 = scm4/scm2**2
     gTotalRS = Limit
     do i = 1, Limit
        rArray(i) = Draw(i)
     end do
     Call Shell (Limit, rArray)                       <============ this should order the random sample

...

Subroutine Shell (n,bArray)

Implicit None

Integer(4),Intent(in):: n
Real(8),Intent(inout):: bArray(:)

Integer(4):: k, j, ir, i, m
Real(8):: tmp

! Shell Sort adapted from the Numerical Recipies in Fortran

   if (n < 2) Return
   m = n
   k = 1
   do while(k <= m)
      k = 3 * k + 1
   end do
   do while (k > 1)
      k = k / 3
      do i = k + 1, n
         tmp = bArray(i)                 <======= but error is here with i = 3281 and n = 5000 <<<< 1st time at this statement
          j = i
          do while(bArray(j-k) > tmp)
             bArray(j) = bArray(j-k)
             j = j - k
             if(j <= k) EXIT
          end do
          bArray(j) = tmp
       end do
    end do
    return

end subroutine Shell

I've tested Shell on some small datasets and no problems.

Data corruption would be my

Steven_L_Intel1 — Tue, 08 Mar 2016 17:11:39 GMT

Data corruption would be my guess. Since you didn't provide a complete program I can't try it myself, but I would suggest building with all run-time checking options on (/check:all) and also /warn:interface. I'd also recommend running under Intel Inspector XE and asking it to do memory use error checking.

Your subroutine Shell is

jimdempseyatthecove — Tue, 08 Mar 2016 17:28:15 GMT

Your subroutine Shell is using an Assumed-Shape array for bArray(:)

If this subroutine is .NOT. in a module, then you are required to have an interface to the subroutine.

An assumed shape dummy argument is passed an array descriptor

If Shell is called from code that does not know its interface, the argument passed is a reference to the first cell of the array passed (IOW not the reference to an array descriptor)

Jim Dempsey

Steve,

Brooks_Van_Horn — Tue, 08 Mar 2016 18:07:28 GMT

Steve,

How do I invoke Intel Inspector XE in MSVS 2013?

Brooks

Steve, you were right. I had

Brooks_Van_Horn — Tue, 08 Mar 2016 18:20:28 GMT

Steve, you were right. I had a design flaw in the calling program before I went into Shell.

Thanks all,

Brooks

Inspector XE is included in

Steven_L_Intel1 — Tue, 08 Mar 2016 19:00:02 GMT

Inspector XE is included in "Professional Edition" and "Cluster Edition" of Intel Parallel Studio XE.

Costs too much for me.

Brooks_Van_Horn — Tue, 08 Mar 2016 20:48:40 GMT

Costs too much for me.

topic Steve, you were right. I had in Intel® Fortran Compiler

Access violation reading location 0xFFFFFFFFFFFFFFFF.

Data corruption would be my

Your subroutine Shell is

Steve,

Steve, you were right. I had

Inspector XE is included in

Costs too much for me.