topic I guess, the first program in Intel® Fortran Compiler

Visual Studio Auto Code Indentation

OMeara__Mark — Wed, 21 Mar 2018 03:43:36 GMT

Hello

This concerns the auto indenting possible in Visual Studio via the Ctrl-K-D command. Current we have the indenting option set to the 'smart' in 'Tools | Options | Text Editor | Fortran | Tabs'.

There are two scenarios where the formatting is wrong:

1. Line continuations in an if condition. e.g.:

if (test == .true. .and. &
test2 == .true)
! Ctrl-K-D places the below inline with the if, no indent.
test = .false;
      ! Would prefer to be indented as below instead
      test = .false;
endif

2. Another issue is when we use the ';' to have an if statement on the one line (because we can!). Using Ctrl-K-D incorrectly indents the subsequent code.

if (test == .true.) then; test = .false.; else; test2 = .false.; endif
       ! Next line is indented when it should not be

Has anyone encountered this issue and found a solution?

I cannot help you with the VS

mecej4 — Wed, 21 Mar 2018 20:22:21 GMT

I cannot help you with the VS editor question, but I notice some problems with the code that you showed. Please read #7 of Dr. Fortran's post, https://software.intel.com/en-us/forums/intel-visual-fortran-compiler-for-windows/topic/275071#comment-1548435, in which he discusses why the == operator should not be used with logical expressions (use .EQV. instead). Instead of "if(test == .true.)", you could probably use the correct and shorter "if(test)".

I guess, the first program

willem_v_ — Sat, 29 Sep 2018 11:53:11 GMT

I guess, the first program should read: (added program statement and declarations, so it can be compiled)

program p
logical test, test2
if (test .eqv. .true. .and. &
test2 .eqv. .true.) then
test = .false.
endif
if (test .eqv. .true.) then; test = .false.; else; test2 = .false.; endif
continue
end

Indeed, as mecej4 noted, use .eqv. in stead of == and use if(test) then ...

findent (https://sourceforge.net/projects/findent/) indents the program as follows:

program p
   logical test, test2
   if (test .eqv. .true. .and. &
      test2 .eqv. .true.) then
      test = .false.;
   endif
   if (test .eqv. .true.) then; test = .false.; else; test2 = .false.; endif
   continue
end

which is more or less what you want.