topic Re: advance =no in Intel® Fortran Compiler

advance =no

roddur — Mon, 12 May 2008 13:45:01 GMT

Dear friends,
while i am running thi following code,
1 implicit none
2 write(*,'(a20)',advance='no')"checking .."
3 call sleep(2)
4 write(*,*) "checked"
5 end

i would expect the program to write "checking .." then wait for 2 sec and the write "checked" in the same line.
instead its waiting for two second and writing the whole thing in one go!!! why? am i missing some thing?
thnx in advance

Re: advance =no

Ron_Green — Mon, 12 May 2008 14:02:58 GMT

The runtime library buffers an entire line for stdout. Thus, until the end of line is written, the output is not sent to stdout.

ron

Re: advance =no

Ron_Green — Mon, 12 May 2008 14:39:32 GMT

What you can do is use the $ or edit descriptors instead of non-advancing IO:

write(*,'(a20,$)') "checking ..."

to accomplish what you are after.

The FRTL does recognize a transistion from write to read and will flush the line buffer at the transition. This so that one can do this:

write(*,'(a)',advance='no') "enter the number of elements-> "
read(*,*) i

So that one can create prompts.

In the case of write following write, the FRTL assumes that the user is formatting a complete line using multiple write operations. And again, it waits for the final end-of-line OR $ edit descriptors before flushing the buffer.

I hope this helps.

ron

Re: advance =no

roddur — Mon, 12 May 2008 17:26:49 GMT

thnx...it is working