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    <title>topic Hilbert Transform of 2-D Gaussian Filter in Intel® Integrated Performance Primitives</title>
    <link>https://community.intel.com/t5/Intel-Integrated-Performance/Hilbert-Transform-of-2-D-Gaussian-Filter/m-p/909756#M13999</link>
    <description>&lt;P&gt;Is there an IPPmethod that provides the Hilbert transform of the 2-D Gaussian, for computing quadrature pairs?&lt;BR /&gt;&lt;BR /&gt;Also, does anyone know the formula? In 1-D, it is:&lt;BR /&gt;H(x) = 2/sqrt(pi) * G(x) * integral[0-&amp;gt;x/ssqrt(2)] exp(s^2)ds&lt;BR /&gt;where the integral is Dawson's. &lt;BR /&gt;&lt;BR /&gt;If this is OFF TOPIC then please, all you experts, point me to a forum where I might find my answer.&lt;/P&gt;</description>
    <pubDate>Tue, 05 May 2009 19:37:11 GMT</pubDate>
    <dc:creator>rogene</dc:creator>
    <dc:date>2009-05-05T19:37:11Z</dc:date>
    <item>
      <title>Hilbert Transform of 2-D Gaussian Filter</title>
      <link>https://community.intel.com/t5/Intel-Integrated-Performance/Hilbert-Transform-of-2-D-Gaussian-Filter/m-p/909756#M13999</link>
      <description>&lt;P&gt;Is there an IPPmethod that provides the Hilbert transform of the 2-D Gaussian, for computing quadrature pairs?&lt;BR /&gt;&lt;BR /&gt;Also, does anyone know the formula? In 1-D, it is:&lt;BR /&gt;H(x) = 2/sqrt(pi) * G(x) * integral[0-&amp;gt;x/ssqrt(2)] exp(s^2)ds&lt;BR /&gt;where the integral is Dawson's. &lt;BR /&gt;&lt;BR /&gt;If this is OFF TOPIC then please, all you experts, point me to a forum where I might find my answer.&lt;/P&gt;</description>
      <pubDate>Tue, 05 May 2009 19:37:11 GMT</pubDate>
      <guid>https://community.intel.com/t5/Intel-Integrated-Performance/Hilbert-Transform-of-2-D-Gaussian-Filter/m-p/909756#M13999</guid>
      <dc:creator>rogene</dc:creator>
      <dc:date>2009-05-05T19:37:11Z</dc:date>
    </item>
    <item>
      <title>Re: Hilbert Transform of 2-D Gaussian Filter</title>
      <link>https://community.intel.com/t5/Intel-Integrated-Performance/Hilbert-Transform-of-2-D-Gaussian-Filter/m-p/909757#M14000</link>
      <description>&lt;DIV style="margin:0px;"&gt;
&lt;DIV id="quote_reply" style="margin-top: 5px; width: 100%;"&gt;
&lt;DIV style="margin-left:2px;margin-right:2px;"&gt;Quoting - &lt;A href="https://community.intel.com/en-us/profile/419953"&gt;rogene&lt;/A&gt;&lt;/DIV&gt;
&lt;DIV style="background-color:#E5E5E5; padding:5px;border: 1px; border-style: inset;margin-left:2px;margin-right:2px;"&gt;&lt;EM&gt;
&lt;P&gt;Is there an IPPmethod that provides the Hilbert transform of the 2-D Gaussian, for computing quadrature pairs?&lt;BR /&gt;&lt;BR /&gt;Also, does anyone know the formula? In 1-D, it is:&lt;BR /&gt;H(x) = 2/sqrt(pi) * G(x) * integral[0-&amp;gt;x/ssqrt(2)] exp(s^2)ds&lt;BR /&gt;where the integral is Dawson's. &lt;BR /&gt;&lt;BR /&gt;If this is OFF TOPIC then please, all you experts, point me to a forum where I might find my answer.&lt;/P&gt;
&lt;/EM&gt;&lt;/DIV&gt;
&lt;/DIV&gt;
&lt;/DIV&gt;
&lt;BR /&gt;If you're looking for the Hilbert Transform there was working 1D versionof in the IPP 5.x&lt;BR /&gt;Presumably, based on that you could buildyour 2D version.&lt;BR /&gt;From implementation point of view you may also want to read something about the analytic signal &lt;A href="http://en.wikipedia.org/wiki/Hilbert_transform#Analytic_representation"&gt;http://en.wikipedia.org/wiki/Hilbert_transform#Analytic_representation&lt;/A&gt; &lt;BR /&gt;&lt;BR /&gt;Hope it helps.&lt;BR /&gt;&lt;BR /&gt;AndrewK</description>
      <pubDate>Tue, 12 May 2009 17:26:55 GMT</pubDate>
      <guid>https://community.intel.com/t5/Intel-Integrated-Performance/Hilbert-Transform-of-2-D-Gaussian-Filter/m-p/909757#M14000</guid>
      <dc:creator>andrewk88</dc:creator>
      <dc:date>2009-05-12T17:26:55Z</dc:date>
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