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IPP 2019 Update 1 DFT Length Limit?

Beer__Austin — Tue, 12 Mar 2019 17:54:49 GMT

Using IPP 2019 Update 1, I get a ippStsSizeErr error whenever I call either of the following functions with a length that's greater than 2^26 (67,108,864).

ippsDFTGetSize_C_64fc()

ippsDFTInit_C_64fc()

This length limit isn't documented anywhere. Is it expected behavior?

This article indicates that the length limit for the DFT is 2^32: https://software.intel.com/en-us/articles/mkl-ipp-choosing-an-fft

Thank you for your time.

Thanks for report. This looks

Gennady_F_Intel — Thu, 14 Mar 2019 04:07:48 GMT

Thanks for report. This looks like a error, we will check.

Hello,

ArtemMaklaev — Fri, 15 Mar 2019 16:12:50 GMT

Hello,

The size variables pSizeSpec, pSizeInit, pSizeBuf in function ippsDFTGetSize have int datatype, therefore only vectors which require auxiliary size less than INT_MAX(32bit) can be processed, i.e.:

for double precision complex DFT (64fc) the length upper bound is 67108863 (2^26 - 1).
for single precision complex DFT (32fc) the length upper bound is 134217727 (2^27 - 1).

for double precision complex FFT (64fc) the length upper bound is 2^27.
for double precision complex FFT (32fc) the length upper bound is 2^28.

You can use DFT from MKL for your task because they support ILP64 for size variables.

Thank you very much for that

Beer__Austin — Fri, 15 Mar 2019 16:28:35 GMT

Thank you very much for that information. It makes sense. I think it might be helpful to others if this information were officially documented in the IPP Developer Reference as well.

Thanks for the issue, we

Gennady_F_Intel — Sat, 16 Mar 2019 03:29:25 GMT

Thanks for the issue, we definitely will update IPPs documentation and existing KB article you referred to as well.