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    <title>topic PARDISO: iterate for LU factors from the originial LU factors in Intel® oneAPI Math Kernel Library</title>
    <link>https://community.intel.com/t5/Intel-oneAPI-Math-Kernel-Library/PARDISO-iterate-for-LU-factors-from-the-originial-LU-factors/m-p/1099948#M23811</link>
    <description>&lt;P&gt;Hi,&lt;/P&gt;

&lt;P&gt;I have a problem in which I do not want to iterate for LU factors using PARDISO from the last iteration of factorisation. Instead, I want the new LU factors to be derived from the original LU factors. This is what I mean:&lt;/P&gt;

&lt;P&gt;PARDISO Iteration 1: Y0 (matrix) -&amp;gt; L0U0 -&amp;gt; X0 (solution)&lt;/P&gt;

&lt;P&gt;Iteration 2: Y1 (Y0 updated) -&amp;gt; L1U1 (derived from L0U0) -&amp;gt; X1&lt;/P&gt;

&lt;P&gt;Iteration 3: Y2 (Y0 updated) -&amp;gt; L2U2 (&lt;STRONG&gt;derived from L0U0&lt;/STRONG&gt;) -&amp;gt; X2&lt;/P&gt;

&lt;P&gt;Iteration 4: Y3(Y0 updated) -&amp;gt; L3U3 &lt;STRONG&gt;(derived from L0U0)&lt;/STRONG&gt; -&amp;gt; X3&lt;/P&gt;

&lt;P&gt;and so on...&lt;/P&gt;

&lt;P&gt;I know using param(4) will get new LU factors from the LU factors from the last iteration; however, what I need is somewhat different as my starting point to find new LU factors remains constant.&lt;/P&gt;

&lt;P&gt;Thanks.&lt;/P&gt;</description>
    <pubDate>Tue, 08 Dec 2015 18:18:28 GMT</pubDate>
    <dc:creator>Sunny_S_1</dc:creator>
    <dc:date>2015-12-08T18:18:28Z</dc:date>
    <item>
      <title>PARDISO: iterate for LU factors from the originial LU factors</title>
      <link>https://community.intel.com/t5/Intel-oneAPI-Math-Kernel-Library/PARDISO-iterate-for-LU-factors-from-the-originial-LU-factors/m-p/1099948#M23811</link>
      <description>&lt;P&gt;Hi,&lt;/P&gt;

&lt;P&gt;I have a problem in which I do not want to iterate for LU factors using PARDISO from the last iteration of factorisation. Instead, I want the new LU factors to be derived from the original LU factors. This is what I mean:&lt;/P&gt;

&lt;P&gt;PARDISO Iteration 1: Y0 (matrix) -&amp;gt; L0U0 -&amp;gt; X0 (solution)&lt;/P&gt;

&lt;P&gt;Iteration 2: Y1 (Y0 updated) -&amp;gt; L1U1 (derived from L0U0) -&amp;gt; X1&lt;/P&gt;

&lt;P&gt;Iteration 3: Y2 (Y0 updated) -&amp;gt; L2U2 (&lt;STRONG&gt;derived from L0U0&lt;/STRONG&gt;) -&amp;gt; X2&lt;/P&gt;

&lt;P&gt;Iteration 4: Y3(Y0 updated) -&amp;gt; L3U3 &lt;STRONG&gt;(derived from L0U0)&lt;/STRONG&gt; -&amp;gt; X3&lt;/P&gt;

&lt;P&gt;and so on...&lt;/P&gt;

&lt;P&gt;I know using param(4) will get new LU factors from the LU factors from the last iteration; however, what I need is somewhat different as my starting point to find new LU factors remains constant.&lt;/P&gt;

&lt;P&gt;Thanks.&lt;/P&gt;</description>
      <pubDate>Tue, 08 Dec 2015 18:18:28 GMT</pubDate>
      <guid>https://community.intel.com/t5/Intel-oneAPI-Math-Kernel-Library/PARDISO-iterate-for-LU-factors-from-the-originial-LU-factors/m-p/1099948#M23811</guid>
      <dc:creator>Sunny_S_1</dc:creator>
      <dc:date>2015-12-08T18:18:28Z</dc:date>
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