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Dear,
About the Intel® FPGA IP for PCI Express: https://www.intel.com/content/www/us/en/programmable/products/intellectual-property/ip/interface-protocols/m-pci-express-protocol.html ,
I want to use it with Cyclone IV GX FPGA Development Kit: https://www.intel.com/content/www/us/en/programmable/products/boards_and_kits/dev-kits/altera/kit-cyclone-iv-gx.html , but about how many LEs on the development board will be occupied? Just an approximately LEs number is OK.
Hope anyone can tell me, thanks!
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Hi BXia,
EP4CGX150 device contains 149,760 of Logic Elements (LEs).
Kindly refer 'Cyclone IV FPGA Device Family Overview' link below - Page 4 (Table 1–2. Resources for the Cyclone IV GX Device Family).
Thank you.
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Hi Calvin Joazer ,
Thanks for your reply.
I know the EP4CGX150 device contains 149,760 LEs. But I just want to know how many LEs will be occupied when I implement the Intel® FPGA IP for PCI Express on Cyclone IV GX FPGA Development Kit.🙂
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Hi BXia,
You can review the project reports by clicking (Processing > Compilation Report). It will displays detailed report after project processing.
Refer below link - Page 6
Thank you.
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