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Hello,
it seems that I understand something wrong about the representation of imagewidth, imageheigth and interlace-properties in the control data packets and would appreciate another opinion about it. For example I have a TPG with 800x480, no interlacing, 4:4:4 RGB and 3 color planes in sequence, each color plane represented in 8 bit. How should the control data packet look like? I thought it should look like 0F 30 02 10 0E 03 on the dout bus, but I observe 0F 00 03 02 02 02 with signal tap. Thanks for reading and best regards AndreasLink Copied
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800 = 0320h
480 = 01E0h Only one nibble (4 bits) of the control information is encoded per word. So the width would be sent as the four nibbles 0, 3, 2, 0. The height would be 0, 1, E, 0. So looking at the 8 bit data values, I would expect something like: 0F 00 03 02 00 00 01 0E 03- Mark as New
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Thanks for your reply, I overread that there is only one nibble in each 8 bit symbol. (and also some other things :D)
I guess between 0E and 03 in the code format you posted should be 00. regards Andreas- Mark as New
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Yes, I did miss a 00 between 0E and 03.
It's amazing sometimes how easy it is to miss a mistake like that even though I know I double checked it before posting...- Mark as New
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This still doesn't explain the erroneous pattern you are seeing.
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I also logged some wrong valid and ready signals. Now everything seems to be fine with the format.
regards Andreas
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