input [11:0] stimulus;reg val; always @(posedge clk) val <=# 1 |(stimulus); what should be the value stored in the register val? Is it the same as saying val = val | stimulus? And does value always store the lower bit of the stimulus since val is just 1 bit but stimulus is 12 bits? Thanks.
The use of the '|' operator in this case is referred to as a reduction operator. val will get the bitwise OR of all the bits in stimulus. So basically if any bit in stimulus is set, val will be a '1', otherwise, it will be '0';It's the same as writing val <= stimulus | stimulus | stimulus ..... | stimulus | stimulus; only obviously signicantly shorter. Jake