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Initializing allocatable arrays to NaN

Hello,

 

A search indicates that this question was asked (in the Fortran for Windows Forum) before, but that was three years ago, and I can't find any update.

I'm using Intel Fortran version16.1 and I'd like to initialize allocatable arrays to NaN to aid in debugging.  I am familiar with the -ftrapuv and -init=snan,array options but it is my understanding they do not work for allocatable arrays.  The answer in the three year old question I found was "it is something we are working on for the future".  It is now the "future", and since that topic is closed, I've opened a new question to ask again.  Has that capability been added?  Or is it still part of future plans?

Chris Harrop

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Black Belt
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Yes, it has been added.  

Yes, it has been added.  -init=snan,.arrays now works for allocatable arrays. Don't use -ftrapuv, it is worthless.

Steve (aka "Doctor Fortran") - https://stevelionel.com/drfortran
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Steve,

Steve,

Thank you very much for that information.  I'm very happy to hear that.  Do you happen to know which version of the compiler added that capability?  I'd like to make a note for my colleagues about version requirements as we have multiple systems with varying, and sometimes fairly old, versions installed.

Thanks again,

Chris

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It was added in 16.0,

It was added in 16.0, although I don't know whether it was an update, or the original release.

              --Lorri

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Lorri,

Lorri,

Thank you.  That is very helpful.  I have no further questions on this topic.

Chris

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