Interrupt service routine with time-out mraa

[BWill15]

I wan't to use an interrupt but with a time-out of a given amount, let's say 0.5 seconds.

https://github.com/intel-iot-devkit/mraa/blob/master/examples/python/hello_isr.py mraa/hello_isr.py at master · intel-iot-devkit/mraa · GitHub

import mraa

import time

import sys

class Counter:

count = 0

c = Counter()

# inside a python interrupt you cannot use 'basic' types so you'll need to use

# objects

def test(gpio):

print("pin " + repr(gpio.getPin(True)) + " = " + repr(gpio.read()))

c.count+=1

pin = 6;

try:

x = mraa.Gpio(pin)

print("Starting ISR for pin " + repr(pin))

x.dir(mraa.DIR_IN)

# https://github.com/intel-iot-devkit/mraa/blob/master/examples/python/hello_isr.py https://github.com/intel-iot-devkit/mraa/blob/master/examples/python/hello_isr.py

x.isr(mraa.EDGE_RISING, test, x)

var = raw_input("Press ENTER to stop")

x.isrExit()

except ValueError as e:

print(e)

[idata · Accepted solution]

Hi,

The http://iotdk.intel.com/docs/master/mraa/gpio_8h.html GPIO class on MRAA doesn't count with a function to set a timeout. If you want to set a timeout I suggest you to create a subroutine that checks the activity on the pin. For example with a loop structure; if the subroutine doesn't detect any trigger on the pin for a time the subroutine can close the loop.

Regards,

Charlie

[BWill15]

This method uses polling with a time-out:

Change the @timeout(0.020) based on your application. Maximal recommended value is 0.035.

@timeout(0.020)

timeout.py

from functools import wraps

import errno

import os

import signal

# http://stackoverflow.com/questions/11901328/how-to-timeout-function-in-python-timeout-less-than-a-se... http://stackoverflow.com/questions/11901328/how-to-timeout-function-in-python-timeout-less-than-a-se...

class TimeoutError(Exception):

pass

def timeout(seconds=10, error_message=os.strerror(errno.ETIME)):

def decorator(func):

def _handle_timeout(signum, frame):

raise TimeoutError(error_message)

def wrapper(*args, **kwargs):

signal.signal(signal.SIGALRM, _handle_timeout)

signal.setitimer(signal.ITIMER_REAL,seconds) # used timer instead of alarm

try:

result = func(*args, **kwargs)

finally:

signal.alarm(0)

return result

return wraps(func)(wrapper)

return decorator

hcsr04.py

import mraa

import time

from timeout import timeout

trig = mraa.Gpio(3)

echo = mraa.Gpio(4)

trig.dir(mraa.DIR_OUT)

echo.dir(mraa.DIR_IN)

# http://stackoverflow.com/questions/11901328/how-to-timeout-function-in-python-timeout-less-than-a-se... http://stackoverflow.com/questions/11901328/how-to-timeout-function-in-python-timeout-less-than-a-se...

@timeout(0.020)

def distanceUS():

tZero = time.time()

# reading sensor in Python takes about 6 ms (US = Utrasonic Sensor)

# http://stackoverflow.com/questions/32300000/galileo-and-ultrasonic-error-when-distance-less-than-4cm http://stackoverflow.com/questions/32300000/galileo-and-ultrasonic-error-when-distance-less-than-4cm

# http://playground.arduino.cc/Main/UltrasonicSensor http://playground.arduino.cc/Main/UltrasonicSensor

trig.write(0)

time.sleep(0.000004) # in Arduino 2 microseconds, double this value to be sure

trig.write(1)

time.sleep(0.00001) # in Arduino 5 microseconds, double this value to be sure

trig.write(0)

sig = None

nosig = None

etUS = None

while echo.read() == 0:

nosig = time.time()

while echo.read() == 1:

sig = time.time()

if sig == None or nosig == None:

return 0

# et = Elapsed Time

etUS = sig - nosig

distance = etUS * 17150

return distance

while True:

try:

print distanceUS()

except Exception, e:

# print 'time out!'

continue