Nios® V/II Embedded Design Suite (EDS)
Support for Embedded Development Tools, Processors (SoCs and Nios® V/II processor), Embedded Development Suites (EDSs), Boot and Configuration, Operating Systems, C and C++

PeriodL & PeriodH

Altera_Forum
Honored Contributor II
1,633 Views

I understand that timeout period determines the period of your interrupt.  

I also understand that periodL and periodH is holds the LSB and MSB 16bit value of the period register.  

My question is how do i know what value to put into these registers to change my timeout period?
0 Kudos
3 Replies
Altera_Forum
Honored Contributor II
311 Views

period register = timeout period x timer frequency 

For example if your timer runs at 50Mhz and you need a 50ms period, you must 

write the period register 0.05 x 50M = 2500000. 

2500000 dec = 2625a0 hex : then periodH = 0x26 and periodL = 0x25a0.
0 Kudos
Altera_Forum
Honored Contributor II
311 Views

It seems strange to me that Altera haven't supplied 32bit versions of the timer devices. I presume the 16bit versions have been carried forwards from an earlier design - It isn't as though a 32bit version would be difficult to write from scratch! 

 

It is worth checking that you don't need to subtract 1 from the count - check the datasheet/pdf.
0 Kudos
Altera_Forum
Honored Contributor II
311 Views

Sorry, actually the correct formula is: 

period register = timeout period x timer frequency - 1 

Thanks to dsl for pointing out the mistake.
0 Kudos
Reply