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printf() after IORD always -1

Altera_Forum
Honored Contributor II
1,070 Views

Hi, 

I wrote a very simple Verilog module. This module is an Avalon slave on Nios II. It has 2 registers that can be read and write. I implemented it on a SoPC with where I created: 

-the Nios II 

-the jtag 

-the SDRAM 

-my Verilog module. 

I instantied this SoPC on a Top level module also with a PLL to give the right clock to SDRAM. I'm using a DE0 Nano board. 

Then I wrote also a simple C program: 

 

#include "system.h"# include "stdio.h"# include "io.h" # define REG_BASE (*(volatile unsigned int*) REGISTRI_0_BASE) int main(){ long int a,b; a=IORD(REG_BASE, 0); printf("%ld",a); IOWR(REG_BASE, 0, 12); IOWR(REG_BASE, 1, 1); a=IORD(REG_BASE, 0); printf("%ld",a); b=IORD(REG_BASE, 1); printf("%ld",b); while(1){ }; } 

 

This program give this output: 

-1 -1 -1 

But i expected 

0 12 1 

Do you know why? Do you need my verilog code? 

Thank you
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Altera_Forum
Honored Contributor II
346 Views

The verilog would probably help. Thanks!

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