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MAX10 Signal propagation

EEren
Beginner
1,015 Views

I have a mux

F_LPTG_OUT(0) <= F_LPTG_IN(0) when (sel(0) = '1') else cpu_out(0);

What signal propagation time will be from the input to the output?

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7 Replies
Kenny_Tan
Moderator
109 Views

basically, you have a mux which means there will be 3 input to one output. we calculate the delay base on register to register in time quest.

You should be able to pull out the delay from the time quest for the delay that you have.​

EEren
Beginner
109 Views

I go to Time Quest -> Custom Reports -> Report Path. Fill From and To.

report_path -from [get_ports {F_LPTG_IN[0]}] -to [get_ports {F_LPTG_OUT

[0]}] -npaths 1 -panel_name {Report Path} -multi_corner

I get - Report Path: No paths were found

EEren
Beginner
109 Views

OK. I did it. I got a delay from input to output 9.378 nanosec. It's awful. I need 2-3 nanosec. What can I use faster then mux?

Kenny_Tan
Moderator
109 Views

As mention, timequest report path from reg to reg. You need to see what reg to reg on the path that you interest and report from there. In the btw the register, you have to manually add in the delay to sum out the delay of your path.​

EEren
Beginner
109 Views

I have fast switching signals. Maxsimum delay 3 nanosec. I got 9.378. What can I use to commutate inputs to output faster?

a_x_h_75
New Contributor III
109 Views

If you need it to be quicker, and that's the only way to design it, then you'll need a faster speed grade device or, more likely, a faster device family. MAX 10 isn't particularly fast.

 

Where are these signals coming from? I'm assuming they're from device pins...

 

Cheers,

Alex

sstrell
Honored Contributor III
109 Views

If you are looking at a report from an input of the device all the way to an output, you're looking at the total delay through the entire device, so of course it might be large. Can you clarify exactly what reporting command you used that worked and also where the registers are in this design?

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