Seeing intrinsic function results in debugging

cacciatore · ‎12-21-2002

While debugging my projects, I can't see the result of an intrinsic function in Watch or QuickWatch. The projects are built using Debug Active Configuration. If I try to watch the value of, for example, ALOG10(DISTANCIA), the " undefined variable ALOG10" apears in place of the value of ALOG10(DISTANCIA).
In Project Settings, Fortran/Debug Debugging Level is Full, and have the " use program database for debug information" checked. Tried checking " Compile debugg(D)Lines" but it didn't work.
Is there any setting I am missing, or what I want is not possible?
Thanks for any hint
Geraldo

Steven_L_Intel1 · ‎12-21-2002

Not possible. Watch is for variables (and subobjects of variables) only.

Steve

Intel_C_Intel · ‎12-23-2002

Actually, watch even allows fairly complicated
expressions, for example X**2.5+X-5.

Steven_L_Intel1 · ‎12-23-2002

Ok - variables and constants. But not function calls.

Steve

faizhoda · ‎03-24-2003

I am not able to watcg even user-defined type variables and their memebers. Do I need to have some special settings to view them?

Steven_L_Intel1 · ‎03-24-2003

You need to have run Per-User Setup from the Visual Fortran program group.