Syntax of a logical expression containing a logical function.

[OP1]

Could someone help me understand (or point at the right place in the IVF documentation) why the commented line in the following code doesn't work (the compiler issues a #6423 error), while the line above does? This is with IVF 11.1.

Thanks,
Olivier

[fortran]MODULE MY_MODULE IMPLICIT NONE CONTAINS LOGICAL FUNCTION MY_FUNCTION MY_FUNCTION = .TRUE. END FUNCTION MY_FUNCTION END MODULE MY_MODULE PROGRAM MY_PROGRAM USE MY_MODULE IMPLICIT NONE IF (MY_FUNCTION()) THEN !IF (MY_FUNCTION) THEN WRITE(*,*) 'Hi!' END IF END PROGRAM MY_PROGRAM[/fortran]

[Anonymous66]

The parentheses after the function name in the call to MY_FUNCTION are a part of standard Fortran syntax.If any variables are passed to the function, they are put inside of the parentheses and they are necessary to distinguish between function and variable names.

[OP1]

OK - Thanks Annalee. I guess I assumed a little too quickly that the parenthesis were optional when the function does not have any arguments.

Olivier