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Ivan_K_6
Beginner
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Memory consumption of the symbolic factorization step (phase 11) in PARDISO

I am using the out-of-core `pardiso` with 3,267,775,116 non-zero entries.

Are there any estimates how much RAM phase 11 should take? I understand that this is the METIS symbolic factorization. Is there a way to get finer control for this stage?

I have tried to use a user-defined permutation (setting `iparm[4]=1`, and the permutation arrya `perm = (MKL_INT) 1..N`). This was to no avail.

Currently, I am getting 120GB of RAM used, which utterly defeats the purpose of the out-of-core part for the rest of the code.

Thank you.

 

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Ivan_K_6
Beginner
48 Views

I would also like to add that the stage in question (11) is also the slowest one. Even with `iparm[1]` = 3 (which I assume should employ an openMP routine of some sort), there is only one thread being used, which hangs for over 30 minutes (100% user time, no system time).

I could not find any documentation on what phase `11` actually does - other than "analysis" (https://software.intel.com/en-us/node/521690).

Again, thanks for the support!

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Hi Ivan,

Currently MKL pardiso doesn't support ability to estimate size of RAm needed for reordering step. However i am bit surprised that reordering step spent most time of whole solution. Can i ask you to sent me the matrix to check what's happened and why reordering step provide poor performance? Probably such behaviour could be resolved.

Thanks,

Alex

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