Allocatable array with 0 base?

[Adrian_F_1]

Is it possible to allocate an array, but have 0 as its base?

I know non-allocatable is easy with integer :: fred(0:10)

But I'm not sure how to do it with an allocatable array

[Arjen_Markus]

Not much different than with declarations:

allocate( fred(0:10) )

[Adrian_F_1]

Arjen Markus wrote:

Not much different than with declarations:

allocate( fred(0:10) )

oh dear, I'm sure I tried that a few months ago and it didn't work.  anyway works fine now thanks

[Steven_L_Intel1]

Make sure you didn't try something like this:

real, allocatable :: fred(0:)
...
allocate (fred(0:10))

The declaration of fred has to be with (:) - no lower bound. If you have a lower bound, then it can't be allocatable (could be a dummy argument.)

[Adrian_F_1]

Steve Lionel (Intel) wrote:

Make sure you didn't try something like this:

real, allocatable :: fred(0:)
...
allocate (fred(0:10))

The declaration of fred has to be with (:) - no lower bound. If you have a lower bound, then it can't be allocatable (could be a dummy argument.)

I may well have done that.  Thanks for the heads up.