How to convert characters to integers

[cldblau]

I need to convert a character string to an integer. The string looks like:

112###### (where # ara blank spaces) and is defined as follows:

character crecy*13

Can anyone help me?

Thanks

[Steven_L_Intel1]

This is a common question to those new to Fortran. The Fortran way of doing this is not to call a routine, as in other languages, but to use a special form of I/O statements called "internal I/O". With internal I/O, you specify a character variable in place of the unit number. You can do formatted or list-directed internal I/O. (You can even use character arrays, in which eash array element is considered a "record".)

So in your case you would want something like:

READ (CRECY, '(BN,I13)') intvar

Some people would use list-directed (format *) here, but I recommend against it because list-directed is too permissive in what it will accept. If you know that the input is always a well-formed integer, you can use:

READ (CRECY, *) intvar

instead.

[cldblau]

Thanks a lot Steve, it works!!!