Intel® Fortran Compiler
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How to set stack size while building in sublime text?

Yeldon_Y_
Beginner
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I've got this problem while I am trying to build fortran in sublime text.

 

Here is what I wrote in sublime text. It works well except for stack size. When I am trying to compile, it says

ifort: command line warning #10006: ignoring unknown option '/stack:0×1500000000'

 

Here is my code in sublime, if someone would like to help me with it.

{
  "cmd": ["cmd", "/e:on", "/v:on", "/c","ipsxe-comp-vars intel64 vs2012 && ifort  ${file} -stack:0×1500000000" ],    
    "file_regex": "^.*\\\\([0-9A-Za-z_]+\\.[A-Za-z0-9]+)\\(([0-9]+)\\):[ ]+error[ ]+#([0-9]+):[ ]+(.*)$",    
    "working_dir":"${file_path}",     
    "selector":"source.f ,source.for ,source.ftn ,source.f90 ,source.fpp ,source.i ,source.i90",  
    "encoding":"cp936",  
    "path":"C:\\Program Files (x86)\\Intel\\Composer XE 2013\\bin;${path}",
    "variants":  
      [    
           {    
              "name": "Run",   
              "cmd": ["cmd", "/e:on", "/v:on", "/c", "ipsxe-comp-vars intel64 vs2012 && ifort ${file} && ${file_base_name}"]  
              }

      ]
}

 

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JVanB
Valued Contributor II
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I see two possible problems. First, I think ifort needs a -link switch before the -stack:0x1500000000 switch. Also, your 0x is coming out more like 0× a multiplication operator rather than the letter x. Try to make sure that's not an issue.

 

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mecej4
Honored Contributor III
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The compiler and the linker do not use the same syntax for specifying the stack size. You can use the /link switch as Repeat Offender stated or you can use the compiler's format:

      /F<n>     set the stack reserve amount specified to the linker

 

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