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Intel ifc compiler

richardwong
Beginner
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Does the latest ifc support complex hyperbolic functions such as cosh? If not, why not?
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Steven_L_Intel1
Employee
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cosh is supported. Which other routines did you want?
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richardwong
Beginner
980 Views
I know real hyperbolic functions are supported but I do not think the complex hyperbolic functions are supported by ifc.
e.g. complex z, z1
z=(1,1)
z1 = cosh(z) or ccosh(z)
I can use the function 'ccos' to work around this if 'ccosh' is not available.
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Steven_L_Intel1
Employee
980 Views
You're correct - COSH with a complex argument is not supported by ifort.
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