format syntax error

[Luis2]

Hi

By default the debugger does not detect the format error

print a ! instead print *,a

I have inspected the project properties and can not find how to change this

[Peter]

Quoting - Luis

Hi

By default the debugger does not detect the format error

print a ! instead print *,a

I have inspected the project properties and can not find how to change this

Luis,

What compiler are you using???

[lklawrie]

I think it will be hard for the compiler (any compiler) to detect your intentions here as the print statement has changed with standards:

print a

suggests using a as the format -- no longer do formats have to be numbers and format statements. With some compiler settings, you would probably get an error at runtime.

Linda

[Luis2]

I'm using ivf 10.1

The error is trivial. Simply, I was surprised that is not detected at compile time.

Perhaps an formated output can not be detected,but I thought that

print a

is an easily detectable error

[lklawrie]

variable a could just as easily be defined as "('type this here')"

and thus print a would produce:

type this here

on the output line.

in old style fortran, any kind of variable could hold a string. that's why i say it might be detected during runtime but not perhaps during compile time.

Linda

[Steven_L_Intel1]

When I compile this program:

[plain]      print a
      end[/plain]

I get:

t.f90(1): error #6304: This format specifier must be of type INTEGER.
print a
------------^
compilation aborted for t.f90 (code 1)

The syntax of the PRINT statement is:

PRINT format [, output-item-list]

Now here's where it gets interesting. When you look at the F2003 standard, format is allowed to be one of:

• default-char-expr
• label
• *

If it's a character expression (could be a variable), then the expression contains a ...




print a
-----------^
t.f90(2): error #5503: Variable 'A' has not been assigned a label in this program unit.
print a
-----------^

But I note that if I don't ask for standards checking, I still get the second error.

So.. I assume that in Luis' program, variable a is declared character. Depending on what is in that character string, one might see almost ...

[TimP]

Certain compilers, such as gfortran, will check the contents of a constant format string at compile time. Some of those checks happen with ifort only at run time, perhaps only when -check format has been set at compile time, and only when use of the format is attempted. The run-time check has the advantage of applying to variable as well as constant formats, but the disadvantage of not catching problems not exposed by a test run. The function of the debugger would be to help determine what led up to the problem, perhaps not needed in the present case.

[Luis2]

I would not expect the debugger to do anything with this. The program should generate a run-time error.

Yes, in my first post I should have written compiler, not debugger

In my little program a is a character

program main
character(len=5) a; a='foo' ; print a
end program

but the compiler does not catch any error, as expected the program crash when I run it.

It really is a bug when I was writing a code, I Do not expect the statement works in a different way.

[Peter]

Quoting - Luis

Yes, in my first post I should have written compiler, not debugger

In my little program a is a character

program main
character(len=5) a; a='foo' ; print a
end program

but the compiler does not catch any error, as expected the program crash when I run it.

It really is a bug when I was writing a code, I Do not expect the statement works in a different way.

Oh!!... That makes a lot of difference when you say 'debugger' instead of 'complier'.

Possibly it might be expecting a namelist, while it is compiling; when you debug it gets upset since it wasnt namelist ! Thesyntax for Print for namelist is
print nml
where
nml=Is the nonkeyword form of a namelist specifier (no NML=) indicating namelist formatting.

This might be a possibility only!

[Steven_L_Intel1]

I already explained that this program is perfectly valid Fortran syntax, which is why the compiler did not complain. It thought you had a run-time format string in variable A. Since you didn't, you got an error at run-time.

[Luis2]

I understand

program main
character(len=5) a
a='("foo")'
print a ! foo
end program

Thank you