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fpp error

nrelhpc
Beginner
1,205 Views

Hi,

I'm trying to use Intel Fortran compiler to compile an application, which produce  an error during configure when running the following command:

fpp -P conftest.c

And the conftest.c is the following:

# include <assert.h>

The error message is

assert.h(106): #error: #if: syntax error.

I tried both intel 2018 and 2020 compiler, and the same thing happened. Does anybody happen to know what may cause this and how to solve it? Many thanks!

 

Hai

 

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7 Replies
Steve_Lionel
Honored Contributor III
1,200 Views

There should be no space between # and include. All fpp directives are # followed immediately by the keyword.

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nrelhpc
Beginner
1,198 Views

Thank you Steve for the suggestion. I deleted that space but got the same error message.

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nrelhpc
Beginner
1,191 Views

I found the problem is caused by the following line:

#if defined __STDC_VERSION__ && __STDC_VERSION__ >= 201112L

fpp doesn't like the long integer 201112 expressed with a suffix “L”. If I deleted that "L", it then passes the test. But this is a system file and I should not change it.

Hai

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IanH
Honored Contributor II
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Why are you pre-processing C source code (the file has a .c extension) with a Fortran preprocessor?

If that file actually contains Fortran source code, why is it trying to include a C standard library header?

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Steve_Lionel
Honored Contributor III
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To add to what Ian said, you aren't using a Fortran compiler at all, just a Fortran-oriented preprocessor.

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nrelhpc
Beginner
1,167 Views

Hi Steve and Ian,

Thanks for the reply. This is performed by a "configure" script, and I have no idea why it wants to do this. But since this test doesn't pass, the "configure" won't allow me to install this application.

 

Hai

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Steve_Lionel
Honored Contributor III
1,159 Views

There's an error in the configure script, then. It should not be trying to use fpp on C sources.

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