how to use Xcode 4.2.1 with ifort?

[changks888]

Dear all,

I like to debug my fortran code using GUI debugger.

I follow the guideline: (1) open a new project; (2) open a new empty file to built fortran code; (3) add build rule under build rule (choose Fortran source files for process using intel fortran XE).

However, the output window shows: GNU gdb 6.3.50-20050815 (Apple version gdb-1708) (Thu Nov 3 21:59:02 UTC 2011) Copyright 2004 Free Software Foundation, Inc. GDB is free software, covered by the GNU General Public License, and you are welcome to change it and/or distribute copies of it under certain conditions. Type "show copying" to see the conditions. There is absolutely no warranty for GDB. Type "show warranty" for details. This GDB was configured as "x86_64-apple-darwin".tty /dev/ttys000 [Switching to process 19571 thread 0x0] Hello World! Program ended with exit code: 0

Do I miss something here?

Thanks, Michael

[Steven_L_Intel1]

Please note that gdb, which is the only debugger you can access from Xcode, does not understand Intel Fortran. For that reason we recommend using "idb" from outside Xcode to debug Fortran programs. I am not all that familiar with the Mac environment, but my guess is that gdb doesn't recognize where to set the initial breakpoint in the code and the program simply runs to completion.