if then or min/max ?

[drob__douglas]

Hello All,

Which would execute quicker? This

Code:

IMIN = INT((XP-XMIN-RMAX)/DX) + 1
IMAX = INT((XP-XMIN+RMAX)/DX) + 1
IMIN = MAX(IMIN,1)
IMAX = MIN(IMAX,NR)      
JMIN = INT((YP-YMIN-RMAX)/DY) + 1
JMAX = INT((YP-YMIN+RMAX)/DY) + 1
JMIN = MAX(JMIN,1)
JMAX = MIN(JMAX,NR)  

or this,

Code:

IMIN = INT((XP-XMIN-RMAX)/DX) + 1
IMAX = INT((XP-XMIN+RMAX)/DX) + 1
IF (IMIN .LT. 1) IMIN = 1
IF (IMAX .GT. NR) IMAX = NR
JMIN = INT((YP-YMIN-RMAX)/DY) + 1
JMAX = INT((YP-YMIN+RMAX)/DY) + 1
IF (JMIN .LT. 1) JMIN = 1
IF (JMAX .GT. NR) JMAX = NR

or is the compiler smart enough to make themequvalent?

Thanks in advance.

- Doug

[Intel_C_Intel]

compiler is smart enough.