what is the meaning of: FNAME1 = 'GNOUT'//A(I,J) and A(10,10)*3

[Rasoul_K_]

A subroutne populates a matrix A(10,10) as follows (actually it doesn't populate last two rows):

       SUBROUTINE GLNAM(I,J,FNAME1,FNAME2)

      CHARACTER FNAME1*10, FNAME2*10,A(10,10)*3,B(10,10)*3

      DATA A(1,1),A(1,2),A(1,3),A(1,4)/'1M1','1M2','1M3','1M4'/
      DATA A(2,1),A(2,2),A(2,3),A(2,4)/'2M1','2M2','2M3','2M4'/
      DATA A(3,1),A(3,2),A(3,3),A(3,4)/'3M1','3M2','3M3','3M4'/
      DATA A(4,1),A(4,2),A(4,3),A(4,4)/'4M1','4M2','4M3','4M4'/
      DATA A(5,1),A(5,2),A(5,3),A(5,4)/'5M1','5M2','5M3','5M4'/
      DATA A(6,1),A(6,2),A(6,3),A(6,4)/'6M1','6M2','6M3','6M4'/
      DATA A(7,1),A(7,2),A(7,3),A(7,4)/'7M1','7M2','7M3','7M4'/
      DATA A(8,1),A(8,2),A(8,3),A(8,4)/'8M1','8M2','8M3','8M4'/
      DATA A(1,5),A(1,6),A(1,7),A(1,8)/'1M5','1M6','1M7','1M8'/
      DATA A(2,5),A(2,6),A(2,7),A(2,8)/'2M5','2M6','2M7','2M8'/
      DATA A(3,5),A(3,6),A(3,7),A(3,8)/'3M5','3M6','3M7','3M8'/
      DATA A(4,5),A(4,6),A(4,7),A(4,8)/'4M5','4M6','4M7','4M8'/
      DATA A(5,5),A(5,6),A(5,7),A(5,8)/'5M5','5M6','5M7','5M8'/
      DATA A(6,5),A(6,6),A(6,7),A(6,8)/'6M5','6M6','6M7','6M8'/
      DATA A(7,5),A(7,6),A(7,7),A(7,8)/'7M5','7M6','7M7','7M8'/
      DATA A(8,5),A(8,6),A(8,7),A(8,8)/'8M5','8M6','8M7','8M8'/
      DATA A(1,9),A(1,10)              /'1M9','1M0'/
      DATA A(2,9),A(2,10)              /'2M9','2M0'/
      DATA A(3,9),A(3,10)              /'3M9','3M0'/
      DATA A(4,9),A(4,10)              /'4M9','4M0'/
      DATA A(5,9),A(5,10)              /'5M9','5M0'/
      DATA A(6,9),A(6,10)              /'6M9','6M0'/
      DATA A(7,9),A(7,10)              /'7M9','7M0'/
      DATA A(8,9),A(8,10)              /'8M9','8M0'/

     FNAME1 = 'GNOUT'//A(I,J)

What is the meaning of '*3' in character A(10,10) *3

Also what is the meaning of: FNAME1 = 'GNOUT'//A(I,J)

what sort of function is: // before A(i,j)

I deleted B inputs with data command as it is same as A

[A__Valle]

The *3 denotes the length of the character (see also http://software.intel.com/sites/default/files/m/3/1/3/1/a/14323-406092.pdf chapter 5 on the character data type) A character expression consists of a character operator (//) that concatenates two operands of type character. (see also http://software.intel.com/sites/default/files/m/3/1/3/1/a/14323-406092.pdf chapter 6 on the character expressions) Hope this helps Dirk

[Rasoul_K_]

D.W. van Meeuwen wrote:

The *3 denotes the length of the character (see also http://software.intel.com/sites/default/files/m/3/1/3/1/a/14323-406092.pdf chapter 5 on the character data type)

A character expression consists of a character operator (//) that concatenates two operands
of type character. (see also http://software.intel.com/sites/default/files/m/3/1/3/1/a/14323-406092.pdf chapter 6 on the character expressions)

Hope this helps

Dirk

Dear Drik Thanks for your input. I will check those sites.

[Anthony_Richards]

Alternatively, you can create the data using internal writes to character variables: DO I=1,8 DO J=1,9 WRITE(A(i,j),'(I1,A1,I1)') i,'M',j ENDDO WRITE(A(i,10),'(I1,A1,I1)') i,'M',MOD(J,10) ENDDO or alternatively, DO I=1,8 DO J=1,10 WRITE(A(i,j),'(I1,A1,I1)') i,'M',MOD(J,10) ENDDO ENDDO Note that Rows 9 and 10 of array A are uninitialised.

[Rasoul_K_]

I down laoded the first file but it is damaged and I couldn't open it. I have to download it again.

[A__Valle]

Please note that the two files are the same, it is the Intel(R) Fortran Language Reference. Dirk

[Rasoul_K_]

D.W. van Meeuwen wrote:

Please note that the two files are the same, it is the Intel(R) Fortran Language Reference.

Dirk

I haven't downloaded the 2nd file yet, but their file size is different.

[A__Valle]

The link is exactly the same. This might be the reason that the first file is damaged...

[Rasoul_K_]

Anthony Richards wrote:

Alternatively, you can create the data using internal writes to character variables:

DO I=1,8
DO J=1,9
WRITE(A(i,j),'(I1,A1,I1)') i,'M',j
ENDDO
WRITE(A(i,10),'(I1,A1,I1)') i,'M',MOD(J,10)
ENDDO

or alternatively,

DO I=1,8
DO J=1,10
WRITE(A(i,j),'(I1,A1,I1)') i,'M',MOD(J,10)
ENDDO
ENDDO

Note that Rows 9 and 10 of array A are uninitialised.

Obviously your solution is smarter than mine, but I couldn't understand it. Could you please explain how these commands produces ((iMj, j=1,10),i=1,8) If the write command doesn't have * or unit number, where the WRITE command is writing?

[Les_Neilson]

It is using what is called "internal I/O" (as Anthony hinted when he said "using internal write") In this case it is not writing to a physical disk file but to a variable. In other words : A(i,j) is the variable being written to (I1,A1,I1) is the format to be used i,'M',j are the variables being written This means that A(1,1) is assigned the value of '1M1' and so on. The result is equivalent to your data assignments but is done in a loop instead. Les

[Rasoul_K_]

I want to use the above formula for generating A(i,j) in the following manner. However it doesn't work. Could you please let me know the correct form? In other words I want to use concatnation in Do loop to produce the desired carachters.

      DO I=1,8
      DO J=1,10
      A(i,j)= i//'M'//MOD(J,10)//'.txt'
      ENDDO
      ENDDO

[Les_Neilson]

You need to replace
A(i,j) = i//'M'//MOD(j,10)//'.txt'
with
WRITE(A(i,j),'(i0,a1,i0,a)') i,'M',mod(j,10),'.txt'

note the use of i0 (i zero) in the format, which allows for "as many digits as are needed" This means that future changes to your program will allow for do loops greater than the ones you currently have.
Assuming of course that A() is a character array of sufficient character length to hold the result.

Les

[Rasoul_K_]

Les Neilson wrote:

You need to replace
A(i,j) = i//'M'//MOD(j,10)//'.txt'
with
WRITE(A(i,j),'(i0,a1,i0,a)') i,'M',mod(j,10),'.txt'

note the use of i0 (i zero) in the format, which allows for "as many digits as are needed" This means that future changes to your program will allow for do loops greater than the ones you currently have.
Assuming of course that A() is a character array of sufficient character length to hold the result.

Les

Dear Les

Thanks for your reply.Where does this "write" takes place? Into monitor or where. I want to produce

A(1,1)= 1M1 and then in next line  want to concatnate it with 'GNOUT' to produce GNOUT1M1 as follows:

FNAME1='GNOUT'//A(i,j)

[Les_Neilson]

In your earlier post you had the following :
  DO I=1,8
      DO J=1,10
         A(i,j)= i//'M'//MOD(J,10)//'.txt'        ! **** this is the line to replace with the code I showed
      ENDDO
   ENDDO

As Anthony and I mentioned in earlier posts it uses "internal I/O" There is no disk file the code "writes" the data from i,'M' and j into the variable A(i,j). You should read about it in a Fortran manual if you want to understand more.

You may then have FNAME1 = 'GNOUT'//A(i,j) just as you have written it .

We assume that you have A() declared as CHARACTER(len=12) :: A(8,10)
or something similar.

Les

[Les_Neilson]

Rasoul,
OK I jumped in a bit quickly there. I should have re-read the original post.
In your first post, there is the line :
    CHARACTER FNAME1*10, FNAME2*10,A(10,10)*3,B(10,10)*3
This means that A is a character array (10,10) the length of each string is 3 characters
and FNAME1 is a single character string of length 10
so your do-loop should have :
     write(A(i,j), '(i1,a1,i1)')  i, 'M', mod(j,10)

Then you can have immediately after that line, (or perhaps in another do-loop further down the code) :
     FNAME1 = 'GNOUT'//A(i,j)//'.txt'
to make what appears to be a file name - however note as I said above FNAME is 10 characters long but
     'GNOUT' is 5 characters long
     A(i,j) is 3 characters long
     and '.txt' is 4 characters long
making 12 characters in total.
This will be truncated and you will lose the 'xt' off the end of the string!
(In other words : you need to make FNAME 12 characters long.)

Hope this helps
Les