Intel® Integrated Performance Primitives
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Why is it so?

tkx007
Beginner
‎03-14-2006 01:28 AM
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int stepMCU2,stepMCU;
Ipp16s* pDstMCU[3];
pDstMCU[0]=ippiMalloc_16s_C1(16,8,&stepMCU2);
pDstMCU[1]=ippiMalloc_16s_C1(8,8,&stepMCU);
Why does 'stepMCU2' and 'stepMCU' both become 32?
I think 'stepMCU' should be 16(8*2=16).
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Vladimir_Dudnik
Employee
‎03-14-2006 01:35 AM
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According IPP manual, ippMalloc use alignment to 32 byte boundary

Vladimir

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tkx007
Beginner
‎03-14-2006 02:18 AM
589 Views
I see,thanks!!
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