- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Good morning dear all,

I'm currently using ippiSqrIntegral_8u32f64f_C1R to compute integral and square integral of an image. The square integral double array resulted seem to be right but it's not the case for the float integral array. So i decided to experiment the function in a simple 512x512 image entirely filled with 255 value. With this case, I expect that every value of integral array is gonna finish with "5" or "0" as it is a sum of 255 values... but i notice that some values can finish with "4" or "7", etc... errors occur between (126,508) and (513,508) .Here is my problem, because even if i'm wrong with the function paramters, it cannot gives float finishing with value other than "0" or "5". Thanks for any help

Here is my code :

#include <vector>

int main(){

std::vector<unsigned char> white(512*512,255);

Ipp8u* src = &white[0];

int step = 0;

Ipp32f* integral = ippiMalloc_32f_C1(512+1,521+1,&step);

Ipp64f* integral2 = (double*)malloc((512+1)*(512+1)*sizeof(double));

IppiSize roi = {w+2*R,h+2*R};

st = ippiSqrIntegral_8u32f64f_C1R(src,512*sizeof(Ipp8u),integral,(512+1)*sizeof(Ipp32f),integral2,(512+1)*sizeof(double),roi,0,0);

if(st!=ippStsNoErr)

{

std::cout << ippGetStatusString(st) << std::endl;

return 1;

}

for(int i=0 ; i<512+1 ; i++)

for(int j=0 ; j<512+1 ; j++)

{

if(*(integral + i*(512+1) + j)%5 != 0)

{

std::cout << i << "," << j << std::endl;

system("PAUSE");

}

}

return 0;

}

Link Copied

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Sorry it is :

IppiSize roi = {512,512};

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

**126,508**or

**513,508**in the file.

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

I just copy-pasted the ouput of command window but the buffer of this window is not big enough to contain all value (it begins only from i=493,j=310). So, i now write directly values in .txt. Please find attached the corresponding output.txt and the .cpp file (where you can change the size of matrix and regenerate output.txt). I don't know why but now , first wrong value occurs at i=129,j=511 (not 126,508) and last one occurs at i=512,j=321 (not 513,508).

Thanks for you help.

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Hi Sergey, any news about integral function... thanks a lot for your help

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Hi Youcef,

Due to limited width of Ipp32f fraction we cannot expect, that adding 255 to Ipp32f value we'll be getting multiple of 5 indefinitely. Look at the code:

[cpp]

Ipp32f sum = 0.;

int i;

for(i = 0; i < 512*512; i++) {

sum += (Ipp32f) 255;

if((sum/5 - (int)(sum/5)) != 0) {

printf("i=%d, sum=%f\n", i, sum);

break;

}

}

[/cpp]

We'll get:

i=65794, sum=16777724.000000

65794/512 = 128.5. I.e. that starting on 129 row you will be not getting 5 or 0 at the end of integral value. That's limitation. If you initialize your src with 5 (instead of 255), you'll get more or less good result.

Regards,

Sergey

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Thanks Sergey, it sounds clear for me now.

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

This is again truncation issue. The expression "a/5.0 - (int)(a/5.0)" is performed with different precision for 'float' and 'double' variables. So, the differences can take place.

Regards,

Sergey

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

**truncation issue**... Sergey, This is Not a truncation issue and this is a precision issue ( 24-bit precision for 'float' vs. 53-bit precision for 'double' ). I simply wanted to stress on the right usage of that term and I understand that there are limitations with accuracy of floating-point calculations. Thanks.

- Subscribe to RSS Feed
- Mark Topic as New
- Mark Topic as Read
- Float this Topic for Current User
- Bookmark
- Subscribe
- Printer Friendly Page