I want convert 8u matrix to 1u matrix using ippiGrayToBin_8u1u_C1R. Can I assume that bits in result have the same order as the source elements? Does this function use big-endian or little-endian format?
Inside one byte of result matrix LSB corespods the first pixel of 8-element frame in the source and MSB corresponds the last pixel.
If we consider memory as continuous sequence of bits, than the result order will be the same as the order in source matrix.