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Cordic sincos function: how to depict a fixed point number as std_logic_vector type

Altera_Forum
Honored Contributor II
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Hello, 

 

i want to use the Cordic sincos IPcore (https://www.altera.com/en_us/pdfs/literature/ug/ug_cordic.pdf). The input is a std_logic_vector in the range of [-pi, pi] for signed configuration case. 

The input consists of: 1bit for sign, 2 bits representing the range, and the rest is the number of fractional bits. 

 

Now, my aim is to make sine calculations for theta from 0 to 360°. 

I want to start by -pi and increment by 1° = 0.017453292 for 360 times to reach one period. 

 

So to cut a long story short:  

- how can i convert the fixed point value into std_logic_vector type? 

- where do i know, where my fractional bits are beginning in the std_logic_vector representation? 

 

 

Thanks in advance and best regards!
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Altera_Forum
Honored Contributor II
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1. No conversion is necessary. You've already said that the IP core uses fixed point representation, so your slv constains fixed point numbers. 

2. With fixed point, each bit represents an decreasing 2^n, with the value in 2s compliment format 

 

So, the MSB will be the sign bit (if signed). 

The integer bits (range bits) just represent standandard integers. 01 = 1, 10 = 2, 11 = 3 etc.  

The fraction bits represent values of 2^n where each value of N is negative,  

 

eg, if you have 4 fracrtion bits, then then 1000 = 0.5, 0100 = 0.25, 0010 = 0.125, 0001 = 0.0625 etc 

So the bits here represent 2^-1 downto 2^-4 etc. 

The more bits you have, the better the accuracy you get. 

 

This is simply just integers with a gain of 2^-N, where N is the number of fraction bits.
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Altera_Forum
Honored Contributor II
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Wouldn't it make more sense to use a simpler unit for angular phase? 

 

There's also a cool discussion explaining how a cordic works, here (http://zipcpu.com/dsp/2017/08/30/cordic.html). Sample code is posted on github (https://github.com/zipcpu/cordic/blob/master/rtl/cordic.v), so you can see what it does an how it works. 

 

Dan
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