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Customer__Intel4

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11-14-2011
06:41 AM

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Efficient storage of sparse matrix with constant non-zero elements

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mecej4

Black Belt

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11-14-2011
07:32 AM

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If any transformation is performed upon or using the special matrix, it will probably cease to have all nonzero values equal to 1. Therefore, the special representation, if it existed, would only apply to the original matrix. It would also be probably necessary to convert (or provide a routine to convert) from the special representation to the usual (ir,jc,v) representation before calling solver routines.

Customer__Intel4

Beginner

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11-14-2011
10:16 AM

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Quoting mecej4

If any transformation is performed upon or using the special matrix, it will probably cease to have all nonzero values equal to 1. Therefore, the special representation, if it existed, would only apply to the original matrix. It would also be probably necessary to convert (or provide a routine to convert) from the special representation to the usual (ir,jc,v) representation before calling solver routines.

mecej4

Black Belt

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11-14-2011
10:54 AM

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u(1:n) = 0

do iz = 1, nnz

c u(ir(iz)) = u(ir(iz)) + val(ir(iz),jc(iz)) * x(jc(iz)) ! general case

u(ir(iz)) = u(ir(iz)) + x(jc(iz)) ! special case

end do

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For more complete information about compiler optimizations, see our Optimization Notice.