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Hi there,
I am having some memory problems regarding the conversion of a CSR matrix to BSR.
Can anyone tell me some links/books/examples regarding that MKL functionality?
Thank you in advance,
Filipe Oliveira
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Hi,
Have you try csr2bsr converter via new Inspector-executor SparseBlas API? The pseusocode for this converter could be represented by following scheme:
sparse_status_t status;
sparse_matrix_t A_csr, A_bsr;
status = mkl_sparse_d_create_csr ( &A_csr, SPARSE_INDEX_BASE_ZERO, m, n, ia, ia+1, ja, val );
status = mkl_sparse_convert_bsr ( A_csr, mblk, SPARSE_LAYOUT_ROW_MAJOR, SPARSE_OPERATION_NON_TRANSPOSE, &A_bsr );
MKL_INT rows=0, cols=0, *ib, *rows_end, *jb, block_size;
sparse_index_base_t indexing;
sparse_layout_t block_layout;
double *b;
status = mkl_sparse_d_export_bsr ( A_bsr, &indexing, &block_layout, &rows, &cols, &block_size, &ib, &rows_end, &jb, &b);
Thanks,
Alex
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In the CSR representation, only the non-zero elements are stored (exception: some routines may require that zero-value elements on the main diagonal should be stored). In the BSR representation, only non-zero blocks are stored.
Thus, if the block-size = 1, the two representations are similar in storage requirements. When the block-size is not equal to 1, on the other hand, if there is at least one non-zero element in any block, all the elements in that block need to be stored (block-wise, it is "store all or none" rule that has to be followed).
As the block-size is increased, the number of within-block zeros that have to be kept will increase. Finally, when the block-size becomes equal to the matrix size, n, the entire n2 elements of the n X n full matrix will have to be kept even in the BSR representation.
I hope that you see now why the memory footprint of a BSR matrix increases when the block-size is increased.
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pls have a look at the <mkldirectory>\examples\spblasc\source\dconverters.c example.
//* TASK 5 Obtain block sparse row matrix from compressed sparse row matrix
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hi there,
thank you for the quick reply. is there any limitation regarding the matrix dimension in CSR format? does it need to squared in order to be convertible to BSR?
i am also getting an strange output of the mkl_scsrbsr(...) conversion. the float *absr array is returning empty even with the correct job config:
job[0] = 0; //If job[0]=0, the matrix in the CSR format is converted to the BSR format;
168 job[1] = 0; //If job[1]=0, zero-based indexing for the matrix in CSR format is used;
169 job[2] = 0; //If job[2]=0, zero-based indexing for the matrix in the BSR format is used;
170 job[3] = 0; //
171 job[4] = 0; //
172 job[5] = 1; //If job[5]>0, all output arrays absr, jab, and iab are filled in for the
regards,
Filipe Oliveira
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Hi,
Have you try csr2bsr converter via new Inspector-executor SparseBlas API? The pseusocode for this converter could be represented by following scheme:
sparse_status_t status;
sparse_matrix_t A_csr, A_bsr;
status = mkl_sparse_d_create_csr ( &A_csr, SPARSE_INDEX_BASE_ZERO, m, n, ia, ia+1, ja, val );
status = mkl_sparse_convert_bsr ( A_csr, mblk, SPARSE_LAYOUT_ROW_MAJOR, SPARSE_OPERATION_NON_TRANSPOSE, &A_bsr );
MKL_INT rows=0, cols=0, *ib, *rows_end, *jb, block_size;
sparse_index_base_t indexing;
sparse_layout_t block_layout;
double *b;
status = mkl_sparse_d_export_bsr ( A_bsr, &indexing, &block_layout, &rows, &cols, &block_size, &ib, &rows_end, &jb, &b);
Thanks,
Alex
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Alexander Kalinkin (Intel) wrote:
Hi,
Have you try csr2bsr converter via new Inspector-executor SparseBlas API? The pseusocode for this converter could be represented by following scheme:
sparse_status_t status;
sparse_matrix_t A_csr, A_bsr;status = mkl_sparse_d_create_csr ( &A_csr, SPARSE_INDEX_BASE_ZERO, m, n, ia, ia+1, ja, val );
status = mkl_sparse_convert_bsr ( A_csr, mblk, SPARSE_LAYOUT_ROW_MAJOR, SPARSE_OPERATION_NON_TRANSPOSE, &A_bsr );
MKL_INT rows=0, cols=0, *ib, *rows_end, *jb, block_size;
sparse_index_base_t indexing;
sparse_layout_t block_layout;
double *b;status = mkl_sparse_d_export_bsr ( A_bsr, &indexing, &block_layout, &rows, &cols, &block_size, &ib, &rows_end, &jb, &b);
Thanks,
Alex
hi there,
is there any relation between mblk and possible memory leaks or incorrect memory acesses? because depending on the block size i get sometimes segmentation fault errors in mkl_sparse_convert_bsr.
Also, is there any mkl debugging tool in OS X?
thank you in advance,
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Hi,
mblk have to be divider of nrows and ncols. In this case could I ask you to send reproducer of this issue to me to understand reason of memory leaks/segfault?
Thanks,
Alex
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Alexander Kalinkin (Intel) wrote:
mblk have to be divider of nrows and ncols.
could you please rephrase this part?
If our matrix is M rows by N columns, our mblk is n*m, N = k*n (k integer), and M = j*m (j integer), does k need to have the same value as j?
Regards,
Filipe Oliveira and Sérgio Caldas
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