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Dear All
From the talbe
http://software.intel.com/en-us/articles/pardiso-parameter-table#table2
It states that
iparm(2)=0 is the MD algorithm and iparm(2)=2 is metis package.
But from the former thread
http://software.intel.com/en-us/forums/topic/299748
"There exists another built-in reordering scheme so called MMD reordering available through iparm(2)=1."
Sergey suggested that iparm(2)=1 is the MD algorithm and iparm(2) = 0 and 2 is metis.
My experience is same as the former thread suggested.
Is the iparm table from your website wrong?
http://software.intel.com/en-us/forums/topic/299748
Hailong
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the description of PARDISO parameters ( http://software.intel.com/en-us/forums/topic/299748) is correct.
in the case of iparm(2) == 1 will be used another built-in reordering scheme so called MMD reordering. We doesn't describe this option because of this reoderening is not validated comprehensively.
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Gennady
Thanks for your help.
So the description of the table http://software.intel.com/en-us/articles/pardiso-parameter-table#table2 is wrong?
It states iparm(2)=0 is MD not metis.
Hailong
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