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Determine load on individual cores

UUser5
Beginner
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Are there any tools to determine the load on individual physical cores, not the virtual ht ones, under linux?

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idata
Employee
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Hello, IAmAnIntelUser:

From our end, there no program such as for Linux, we do have something similar which is the http://www.intel.com/content/www/us/en/support/processors/000005595.html Intel® Turbo Boost Technology Monitor FAQ, but is intended to work with Windows. Since Intel provides limited support for Linux, I would recommend heading to https://www.linux.com/forum Forums | Linux.com | The source for Linux information.

I did a little research and this is what I found;

http://stackoverflow.com/questions/3342889/how-to-measure-separate-cpu-core-usage-for-a-process http://stackoverflow.com/questions/3342889/how-to-measure-separate-cpu-core-usage-for-a-process.

http://stackoverflow.com/questions/20124508/how-to-dynamically-monitor-cpu-per-core-usage-on-linux http://stackoverflow.com/questions/20124508/how-to-dynamically-monitor-cpu-per-core-usage-on-linux.

Hope it helps.

Regards,

Amy.

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UUser5
Beginner
847 Views

Wow

> From our end, there no program such as for Linux, we do have something similar which is the http://www.intel.com/content/www/us/en/support/processors/000005595.html Intel® Turbo Boost Technology Monitor FAQ, but is intended to work with Windows. Since Intel provides limited support for Linux, I would recommend heading to https://www.linux.com/forum Forums | Linux.com | The source for Linux information

This is a server class CPU. Considering that windows only has a minority share among web servers and other enterprise level services (http://www.zdnet.com/article/linux-foundation-finds-enterprise-linux-growing-at-windows-expense/ ZDNet page) , should this not be the other way around?

model name: Intel(R) Xeon(R) CPU E5620 @ 2.40GHz
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idata
Employee
847 Views

I understand, but in this case Intel provides limited support for Linux. You may try posting on https://www.linux.com/forum Forums | Linux.com | The source for Linux information.

Regards,

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