Conversion from output to input base of VHDL module

Altera_Forum · ‎01-13-2010

Hey,everybody.

I am constructing an VHDL code for clock divider and specification of 2 pins.

I need to trigger 2 pins using DE2 board for 1 clock cycle(auto trigger down itself after 1 clock cycle).

However, i have no idea how to convert that output of my clock divider for the clock of my pin specification. Can anyone please help me?

My clock divider convert 27MHz to 500KHz and i need to trigger these 2 pins(buttons from DE2 board) using 500kHz.

My code for the pin specification are:

process(clkin) --- i think my problem is here!!!

begin

if A0 = '1' and (rising_edge(clkin)) then

A0_out <= '1';

count1 := '1';

if count1='1' and (rising_edge(clkin)) then

A0_out<= '0';

count1 := '0';

end if;

end process;

process(clkin)

begin

if convst = '1' and (rising_edge(clkin)) then

convst_out <= '1';

count2 := '1';

if count2='1' and (rising_edge(clkin)) then

convst_out<= '0';

count2 := '0';

end if;

end process;

Altera_Forum · ‎01-13-2010

Hello,

Me, I am used to have a copy of the output signal in these cases.


architecture ...
signal A0_out_s : std_logic;
begin
A0_out <= A0_out_s;
process(clkin)
begin
    if rising_edge(clkin) then        
        if A0_out_s = '1' then
             A0_out_s <= '0';
        elsif A0 = '1' then
             A0_out_s <= '1';
        end if;
    end if;
end process;
end architecture...;

Jérôme