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29282 Discussions

SIZE function on an ALLOCATABLE array

Jon_D
New Contributor II
‎12-31-2015 09:52 AM
965 Views

Hello,

The following code prints out 10 as the size of the ALLOCATABLE array after the array is deallocated. Is this the correct behavior or a compiler bug? I am using the latest version of the Intel Fortran compiler.

Thanks for any clarification.

PROGRAM Main
    IMPLICIT NONE
    
    INTEGER,ALLOCATABLE :: iTestArray(:)
    
    WRITE (*,*) SIZE(iTestArray)
    
    ALLOCATE (iTestArray(10))
    WRITE (*,*) SIZE(iTestArray)
    
    DEALLOCATE (iTestArray)
    WRITE (*,*) SIZE(iTestArray)
    
END

 

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Steven_L_Intel1
Employee
‎12-31-2015 10:48 AM
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It's your error for calling SIZE on an unallocated array. The result of that is undefined.

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andrew_4619
Honored Contributor III
‎01-01-2016 03:37 AM
965 Views

You should use the function allocated(itestarray)

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