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Suppose both `a` and `b` are 1-dimensional array with size n, then we can use `vdexp(n, a, b)` to compute the b = exp(a) with MKL function `vdexp`.
When `a` is a two dimensional array with size n1*n2, which is the efficient way to use `vdexp`, a loop over columns or reshape `a` to a one-dimensional array?
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call vdexp(size(a),a,b)
Jim Dempsey
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