That is the source :
PROGRAM main !1
CHARACTER(LEN=3) :: s !2
!3
s='abc' !4
!5
PRINT*, s(1:1) !6
PRINT*, s(1:2) !7
PRINT*, s(1:3) !8
!9
END PROGRAM main !10
$ifort -g main.f90 ; a.out
a
ab
abc
$ idb a.out
Linux Application Debugger for 32-bit applications, Version 7.3.1, Build 20031003
------------------
object file name: a.out
Reading symbolic information ...done
(idb) stop at "main.f90":3
[#1: stop at "main.f90":4 ]
(idb) run
[1] stopped at [subroutine main():4 0x8049d65]
4 s='abc' !4
(idb) next
stopped at [subroutine main():6 0x8049d87]
6 PRINT*, s(1:1) !6
(idb) next
a
stopped at [subroutine main():7 0x8049dcd]
7 PRINT*, s(1:2) !7
(idb) next
ab
stopped at [subroutine main():8 0x8049e13]
8 PRINT*, s(1:3) !8
(idb) next
abc
stopped at [subroutine main():10 0x8049e59]
10 END PROGRAM main !10
(idb) rerun
Process has exited
[1] stopped at [subroutine main():4 0x8049d65]
4 s='abc' !4
Information: idb allows you to restart the execution of your program
from saved positions. Enter "help snapshot" for details.
(idb) step
stopped at [ function memmove(...) 0x4207bc11]
Information: An type was presented during execution of the previous command. For complete type information on this symbol, recompilation of the program will be necessary. Consult the compiler man pages for details on producing full symbol table information using the '-g' (and '-gall' for cxx) flags.
(idb) step
stopped at [ function memmove(...) 0x4207bc15]
(idb)
Why these messages ? What do they mean ?
Thanks
