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what is the correct function for antilog (0.3)

schaferm
Beginner
‎05-06-2005 07:40 PM
1,461 Views

using Compaq Fortran (1999)

I could not find a simple function for antilog (base 10) of a simple

number- say 0.3

In general, I thought it should be alog10 (0.3) But alog10 of 0.3 gives value of log10 0.3

what is the correct function for antilog (0.3) ?

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Steven_L_Intel1
Employee
‎05-06-2005 07:58 PM
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alog is just log - the a is the Fortran convention for a function that returns a REAL value but the name otherwise would be implicitly INTEGER.

Don't you just want 10.0**number?
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