- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
Hi experts,
im struggling to implement an efficient IPP-based funtion to this simple task:
"add 8u-image to existing float-image without creating an temporary float image."
int img_sz = 1024*768;
float dest_img = new float[img_sz]; //init destination img... //... //now convert incoming 8u image to float and add it to destination image unsigned char* newimg_8u= new unsigned char[img_sz]; //filled somewhere... //create LUT for 8u->float conversion for (int k=0;k<256;++k) m_LUT8bit= k; //time critical part follows //convert it with LUT to float and add the existing float-image //optimize this? for (int k = 0; k < img_sz ; ++k) { dest_img += m_LUT8bit[newimg_8u ]; } delete...
Is there an easy way to do this with IPPs or IPPi?
Link Copied
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
Hello,
Hi,
why does the code need to define m_LUT8bit? Is this just for converting to the float data? A conversion function may be faster.
I does not have inplace add function for this. If the memory for a new float image is too large, possibly it can just provide a short buffer for each line of image data. For example,
Ipp32f buffer[image width];
for ( i=0;i< height; i++){
ippsConvert_8u32f(newimg_8u[in line i], buffer, width);
ippsAdd_32f_I(buffer, dest_img,width);
}
Thanks,
Chao

- Subscribe to RSS Feed
- Mark Topic as New
- Mark Topic as Read
- Float this Topic for Current User
- Bookmark
- Subscribe
- Printer Friendly Page