matrix multiplication using verilog

[Altera_Forum]

I have coded a matrix multiplication. matrix size is 4 by 4 and the data size is 1 bit. It shows some structure in RTL view but nothing is seen is technology map viewer and it shows 0 LEs are used. Please help..... 

//matrix multiplication:  module matmul(clk,a,b,c); input clk,a,b; output reg c; reg sum; reg ra[3:0][3:0]; reg rb[3:0][3:0]; reg rc[3:0][3:0]; integer i1,i2,i3,j1,j2,j3,k;   always@(posedge clk) for(i1=0;i1<=3;i1=i1+1) begin for(j1=0;j1<=3;j1=j1+1) begin ra[i1][j1]=a; rb[i1][j1]=b; end end  always@(posedge clk) for(i2=0;i2<=3;i2=i2+1) begin for(j2=0;j2<=3;j2=j2+1) begin sum=1'b0; for(k=0;k<=3;k=k+1) begin sum=sum^ra[i2][k]*rb[k][j2]; end rc[i2][j2]=sum; end end   always@(posedge clk) for(i3=0;i3<=3;i3=i3+1) for(j3=0;j3<=3;j3=j3+1) c=rc[i3][j3]; endmodule

[Altera_Forum]

Which device are you using? Maths functions are optimized mostly using DSP/embedded multiplier where applicable. But it would be rare to have 0 LEs used at all.

[Altera_Forum]

I'm a bit rusty, but won't 'ra' always be a 4x4 matrix of all ones or all zeros depending on the state of 'a' at the rising edge of clk? And likewise for 'rb'? So the output will always be a 4x4 matrix of zeros since in all cases 'sum' resolves to 0 since the matrix length is even? 

((((0 xor 0*0) xor 0*0) xor 0*0) xor 0*0)=0 ((((0 xor 1*0) xor 1*0) xor 1*0) xor 1*0)=0 ((((0 xor 0*1) xor 0*1) xor 0*1) xor 0*1)=0 ((((0 xor 1*1) xor 1*1) xor 1*1) xor 1*1)=0 Maybe try an odd matrix dimension and see if you get a different result.