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Hello,
I am trying to use PARDISO to solve a sparse linear least-squares problem Ax=b, where A is a m-by-n matrix with m>n. Let's assume I already constructed A in CSR-format.
In order to solve that system using sparse solvers I learned that it is necessary to compute C=(A' A) and d=(A' b) and then solve Cx=d instead (see here). So, I compute C using mkl_?csrmultcsr.
The problem: since C is symmetric, PARDISO expects it to be an upper triangular matrix, which it is not after using mkl_?csrmultcsr. So, the matrix checker (iparm(26)=1) fails.
My question: Is there another function in the MKL which extracts the upper/lower triangular matrix of a whole matrix?
Thank you in advance for you time and suggestions,
Nils
I am trying to use PARDISO to solve a sparse linear least-squares problem Ax=b, where A is a m-by-n matrix with m>n. Let's assume I already constructed A in CSR-format.
In order to solve that system using sparse solvers I learned that it is necessary to compute C=(A' A) and d=(A' b) and then solve Cx=d instead (see here). So, I compute C using mkl_?csrmultcsr.
The problem: since C is symmetric, PARDISO expects it to be an upper triangular matrix, which it is not after using mkl_?csrmultcsr. So, the matrix checker (iparm(26)=1) fails.
My question: Is there another function in the MKL which extracts the upper/lower triangular matrix of a whole matrix?
Thank you in advance for you time and suggestions,
Nils
1 Solution
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Hi,
From my point of view the best solution in this case is to set matrix C as unsymmetric and use full format of matrix C.
With best regards,
Alexander Kalinkin
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Hi,
From my point of view the best solution in this case is to set matrix C as unsymmetric and use full format of matrix C.
With best regards,
Alexander Kalinkin
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Hi Alex,
Thanks for your answer. This is exactly how I am doing it at the moment. I just wondered if there exists another way. So, know I know - thanks!
Regards,
Nils
Thanks for your answer. This is exactly how I am doing it at the moment. I just wondered if there exists another way. So, know I know - thanks!
Regards,
Nils
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