Community
cancel
Showing results for 
Search instead for 
Did you mean: 
Jens_E_
New Contributor I
36 Views

Pardiso: schur complement time usage

Hi, 

I'm computing the schur complement using iparm(36)=1. I do this in phases so that I first perform phase 331, then phase 332 in my own code, and then phase 333 in pardiso.

Prior to this, the schur complement matrix is calculated using phase 12.

It seems to me that one call (phase 331 then 333) with N right-hand sides is a lot faster than, say, 10 calls with N/10 right-hand sides. From the time usage it acutally seems like pardiso refactorizes the matrix for each subsequent call using phase 33x? Could this be?

I expected a single call (many rhs) to be faster than several calls (fewer rhs), but not by what seems to be a 10-fold (using the example above).

Labels (1)
Tags (1)
0 Kudos
0 Replies