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Hi,
in the datasheet of the MAX10 FPGA type10M50DAF484C8GES I read that the on-chip memory has a size of 1,677,312 kbits. This means a size of more than 209 MBye. This seems to be extremely large. Is this correct? Second question: I want to devide this on-chip memory into 24 FIFOs of 2 MByte, 12 bit wide. Can I do this? Thank you. Regards.Link Copied
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For a 10M50 my datasheet says M9K memory (Kb = Kbytes?) is 1638. I take this as 1638 x 1024 =1677312 bits. So ... 1677312/1024= ~1638 KBytes ~= 1.6 MB.
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MAx 10 never own such huge capacity of memory for that cost... else the cyclone V and Arria 10 can retire already...
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and max 10 implementation need to be careful as you can easily used up those spaces.
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BMW
it is in bits not kbits so: 1,677,312 bits == 205KBytes of memory.- Mark as New
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--- Quote Start --- BMW it is in bits not kbits so: 1,677,312 bits == 205KBytes of memory. --- Quote End --- Hi,somewhere I read about 1,677,312 kbits.I can not find it anymore. But I was suspicious about this huge amount ! Thanks for making it clear.! Regards.

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