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How to use floating-point number in verilog code?

Altera_Forum
Honored Contributor II
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Hi, 

 

I would like to ask anyone here can please teach me how to use floating-point number in verilog code? For example, I got a formula,  

 

y=100*p^(1000/5255); 

 

if I enter p=100000, I want my y value=894 

 

Is it possible to do that in verilog? 

 

Thanks. 

 

Best regard, 

TWK
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Altera_Forum
Honored Contributor II
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Verilog has very specific rules about how data types (bit widths, signedness, and realness) are propagated through an expression. 

 

Verilog uses integer arithmetic by default when all operands are integers. You can covert to real arithmetic by using real constants writing:  

 

y - 100.0*p^(1000.0/5200.0);
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Altera_Forum
Honored Contributor II
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--- Quote Start ---  

Is it possible to do that in verilog? 

--- Quote End ---  

 

It's possible to calculate real expressions at compile time, e.g. for constants, but the code isn't synthesizable.
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Altera_Forum
Honored Contributor II
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If you are using constants you could represent them using binary form. 

 

http://davidcastells.blogspot.com.es/2012/07/floating-point-to-fixed-point-online.html
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