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Hello all,
I have a 28 bit local bus. I have a RAM with 7 bit address input 6..0. I need to use the schematic editor to make the RAM address input be connected to bits Local_Bus[6..2] and ground the lower two bits of the RAM address input. To do this I need to concatenate bits from Local_Bus and this Ground bus, which is so very simple in VHDL but after much trying I cannot figure it out in the schematic editor. Here's a graphic to illustrate the situation. It's sort of a "fill in the blanks." Any ideas are greatly appreciated, thanks! :confused:Link Copied
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Hi,
place a bus on the RAM adress input, name it RAM_addr[6..0]. place a bus away (without any connection) and name it RAM_addr[6..2] place "wire" component (which does nothing in logic) It is like "<=" in VHDL, on input connect Local_bus[6..0], on the ouput connect RAM_addr[6..2] .... See my schema for ideas. Good luck.- Mark as New
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Or, more simply, connect to the RAM address input a bus named:
Local_Bus[6..2],Ground[1..0]- Mark as New
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Thanks so much guys, that has really helped me out, and quick. I don't know how I would have done this whole project with out the forums and Altera's quick support responses!

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