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Suppose I have output Q[7..0] of a flipflop A, and output Q[7..0] of a flipflop B, of which I want to connect to the inputs D[15..0] of a flipflop C in such a fashion that:
AQ[0] -> CD[0] BQ[0] -> CD[1] AQ[1] -> CD[2] BQ[1] -> CD[3] AQ[2] -> CD[4] BQ[3] -> CD[5] etc. How can I do that in a schematic design? A related question: Same setup as above, but now I want to connect AQ[7..0] -> CD[7..0] and BQ[7..0] -> CD[15..8], how is this done in a schematic?Link Copied
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Create a .bdf file insert the lpm flip-flops A, B C and D. Right Click on qout select properties to insert the name(s). Right Click on din and select properties to add the source names. Help topic "working with connectors" has more detail.

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