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EEren
Beginner
1,248 Views

MAX10 Dual Boot.

On CFM0 I have a bootloader. I create rpd file from a main project and burn it on CFM1.

After successful burning I switch BOOT_SELECT to boot from CFM1. However the main project

 failed to run and the boot runs.

Where can I find some instructions how to create valid rpd file and burn it into CFM1.

0 Kudos
9 Replies
AnandRaj_S_Intel
Employee
86 Views

Hi,

 

Refer the links and demo projects.

AN 730: Nios II Processor Booting Methods in MAX 10 FPGA Devices

https://fpgacloud.intel.com/devstore/platform/16.0.0/Standard/dualboot-design-example/

https://fpgawiki.intel.com/uploads/0/00/Using_Dual_Boot_MAX_10_Evaluation_Kit.pdf

https://www.intel.com/content/dam/www/programmable/us/en/pdfs/literature/an/an741.pdf

 

Let me know if this has helped resolve the issue you are facing or if you need any further assistance.

 

Best Regards,

Anand Raj Shankar

(This message was posted on behalf of Intel Corporation)

 

 

EEren
Beginner
86 Views

I did as described in the document. However it dosen't work after programming prd file into CFM1. The master project should be configured as a single or a double image?

EEren
Beginner
86 Views

prd file is a binary file. should I reverse bytes before programming? and what is the order of bytes?

this

word_to_write = (UInt32)((reversed_byte[raw_data[i]] << 24) | (reversed_byte[raw_data[i + 1]] << 16) | (reversed_byte[raw_data[i + 2]] << 8) | reversed_byte[raw_data[i + 3]]);

 

or this

word_to_write = (UInt32)((reversed_byte[raw_data[i + 3]] << 24) | (reversed_byte[raw_data[i + 2]] << 16) | (reversed_byte[raw_data[i + 1]] << 8) | reversed_byte[raw_data[i]]);

 

 

EEren
Beginner
86 Views

May be I burn in the wrong sector? in my module flash_update generics are

SECTOR3_START_ADDR => 16384, SECTOR3_END_ADDR => 114687, SECTOR4_START_ADDR => 114688, SECTOR4_END_ADDR => 188415, SECTOR5_START_ADDR => 188416, SECTOR5_END_ADDR => 360447,

As I understood SECTOR5 is CFM0 and SECTOR3-SECTOR4 is CFM1.

AnandRaj_S_Intel
Employee
86 Views

Hi,

 

  1. Project related to dual configuration should be configured as  double image.
  2. Should I reverse bytes before programming? No.

For more information please check the below links.

https://www.youtube.com/watch?v=0k4AZmdW9Sk

https://www.youtube.com/watch?v=Z0l0GrjXn8w

 

Let me know if this has helped resolve the issue you are facing or if you need any further assistance.

 

Best Regards,

Anand Raj Shankar

(This message was posted on behalf of Intel Corporation)

EEren
Beginner
86 Views

I write the rpd file. Let's take the first bytes from the file 50 FF 47 FF. But when I read it back from the flash I get FF 50 FF 47.

What's going on! Who can me explain for for Christ's sake!

AnandRaj_S_Intel
Employee
86 Views

Hi,

 

  1. Bit reversal is required if you have used little-Indian option while generating the .pof file. Which is default.
  2. If Big-Indian option is used bit reversal is not required
  3. Example design is attached

 

Best Regards,

Anand Raj Shankar

(This message was posted on behalf of Intel Corporation)

EEren
Beginner
86 Views

Hi Anand

Thank you for the example.

I have something to clarify

for(address=CFM1StartAddress;address<=CFM1EndAddress;address=address+4) { scanf("%2x%2x%2x%2x",&receivedHex[0],&receivedHex[1],&receivedHex[2],&receivedHex[3]); /*Get 4 bytes from UART Terminal*/ for(byte=0; byte<4; byte++) { receivedHex[byte] = (((receivedHex[byte] & 0xaa)>>1)|((receivedHex[byte] & 0x55)<<1)); /*Swap LSB with MSB before write into CFM*/ receivedHex[byte] = (((receivedHex[byte] & 0xcc)>>2)|((receivedHex[byte] & 0x33)<<2)); receivedHex[byte] = (((receivedHex[byte] & 0xf0)>>4)|((receivedHex[byte] & 0x0f)<<4)); }   word = (receivedHex[0]<<24)|(receivedHex[1]<<16)|(receivedHex[2]<<8)|(receivedHex[3]); /*Combine 4 bytes to become 1 word before write operation*/ IOWR_32DIRECT(ONCHIP_FLASH_0_DATA_BASE, address, word); /*Command to write into On-Chip Flash IP*/ byte = 0; word = 0x0; while((IORD(ONCHIP_FLASH_0_CSR_BASE, 0) & 0x0b) == 0x02) { printf("Writing CFM1(%d)\n",address); } if((IORD(ONCHIP_FLASH_0_CSR_BASE, 0) & 0x0b) == 0x00) { printf("Write to %d failed\n", address); state=20; address = 700000; } if((IORD(ONCHIP_FLASH_0_CSR_BASE, 0) & 0x0b) == 0x08) {   }   }

This part

for(byte=0; byte<4; byte++) { /*Swap LSB with MSB before write into CFM*/ receivedHex[byte] = (((receivedHex[byte] & 0xaa)>>1)|((receivedHex[byte] & 0x55)<<1)); receivedHex[byte] = (((receivedHex[byte] & 0xcc)>>2)|((receivedHex[byte] & 0x33)<<2)); receivedHex[byte] = (((receivedHex[byte] & 0xf0)>>4)|((receivedHex[byte] & 0x0f)<<4)); }

I shouldn't do if I have Big-Indian option or I should swap MSB and LSB anyway?

AnandRaj_S_Intel
Employee
86 Views

Hi,

 

Yes, Shouldn't do if we have Big-Indian option​.

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