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Dear Sir,
I've a question about the pull-up resistor. Suppose, the pull-up resistor is related to the I/O voltage Vccio and current strength, isn't it? Why does it show the resistor is about 10KOhm to 50KOhm in the table5-3 of Cyclone II Device handbook chapter 5? For example, Vccio=3.3V, Current strength 16mA in Default of LVTTL. The pull-up is supposed to be around Rpull-up = (3.3/16)KOhm, isn't it? Regards, Peter ChangLink Copied
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--- Quote Start --- Suppose, the pull-up resistor is related to the I/O voltage Vccio and current strength. --- Quote End --- It isn't. The value is fixed, but subject to PVT (process, voltage, temperature) variations.
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Dear Sir,
But I could see a similar example from the page of 8-3 to 8-5 in the MAXII Device Handbook, max2_mii5v1.pdf. It is for the REXT. It, however, is able to be used for an internal resistor, RINT, isn't it? Regards, Peter Chang:confused:- Mark as New
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In the device handbook, the minimum value for an external pull-up resistor is calculated. The internal pull-up resistor is in contrast a weak pull-up with a resistance several orders of magnitude above this minimum value.
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Dear FvM,
Why do we need both? Suppose, we need only either internal or external resistor, needn't we? Peter Chang- Mark as New
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They each serve a purpose. The extern pull-up discussion e.g. has the title max ii device compatibility with 5.0-v cmos devices.
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Dear FvM,
Do you mean the example is only more like a voltage shiffter? Can the pull-up resistor not be calculated in the same way as the example? Thank you! Peter- Mark as New
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The example is in fact for Multi-IO voltage respectively level conversion, it uses the MAX II output in open-drain configuration. In the example, a minimum value based on the available output current is calculated. But in an application, a higher value may be appropriate.

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